The upper half of an inclined plane of inclination theta is perfectly

For first half acceleration = g sin theta Therefore, velocity after travelling ball distance v^(2) = 2(g sin theta)l For second half, acceleration = g(sin theta - mu(k) cos theta) so 0^(2) = v^(2) = 2g (sin phi - mu(k) cos phi)l Solving (i) and (ii) we get mu(k) = 2 tan theta

Solved] The upper half of an inclined plane of inclination θ is perfect..

The upper half of an inclined plane of inclination θ is perfectly smooth while the lower half is

The upper half of an inclined plane of inclination θ is perfectly smooth while lower half is rough. A block starting from rest at the top of the plane will again come

The upper half of an inclined plane with inclination $\phi $ is perfectly smooth while the lower half is rough. A body starting from rest at the top will again come to

Answer: (a) 22. The upper half of an inclined p lane of inclination is perfectly smooth while the lower half rough. A block starting from rest the of the plane will again

CU 10. W TOUN (B) 500N (l) 349 N The upper half of an inclined plane of inclination is perfectly smooth while the lower half is rough. A body starting from the

The upper half of an inclined plane of inclination andtheta; is perfectly smooth while lower half is rough. A blockstarting from rest at the top of the plane will again come to

The upper half of an inclined plane of inclination theta is perfectly smooth while the lower half rough. A block starting from rest the of the plane will again come to rest

The upper half of an inclined plane with inclination phi is perfectly

11. The upper half of an inclined plane of inclination is perfectly smooth while lower half is rough. A block starting from rest the of the plane will again come to rest